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A point mass oscillates along the x-axis...

A point mass oscillates along the x-axis according to the law `x=x_(0) cos(moegat-pi//4). If the acceleration of the particle is written as `a=A cos(omegat+delta), the .

A

`A = x_(0), delta = -(pi)/(4)`

B

`A = x_(0)omega^(2), delta= (pi)/(4)`

C

`A = x_(0)omega^(2) , delta= -(pi)/(4)`

D

`A - x_(0)omega^(2) , delta=(3pi)/(4)`

Text Solution

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The correct Answer is:
D
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