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Both the strings shown in figure are mode of same material and have same cross-section. The pulleys are light the wave speed of a transverse wave in the string AB is `v_(1)` and in CD it is `v_(2)`. Then `v_(1)//v_(2)` is

A

1

B

2

C

`sqrt(2)`

D

`1//sqrt(2)`

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The correct Answer is:
D
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MOTION-WAVES-EXERCISE -1 (Objective Problems JEE Main)
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  9. Two waves of equal amplitude A, and equal frequency travel in the same...

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