A taut string at both ends viberates in ...

A taut string at both ends viberates in its `n^(th)` overtone. The distance between adjacent Node and Antinode is found to be 'd'. If the length of the string is L, then

L=2d(n+1)

L=d(n+1)

L=2dn

L = 2d(n – 1)

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

WAVES
MOTION|Exercise EXERCISE -2 (Level -II) (Multiple correct JEE Advanced)|14 Videos
WAVES
MOTION|Exercise EXERCISE -3 (Level -I) (Subjective JEE Advanced)|15 Videos
WAVES
MOTION|Exercise EXERCISE -1 (Objective Problems JEE Main)|35 Videos
WAVE OPTICS
MOTION|Exercise EXERCISE - 4 (Level - II) Previous Year | JEE Main|16 Videos
WORK, POWER & ENERGY
MOTION|Exercise Exercise - 3 Section-B|22 Videos

Similar Questions

Explore conceptually related problems

In a pipe open at both the ends the distance between node and antinode is

A string of length L fixed at both ends vibrates in its first overtone. Then the wavelength will be

A stretched string of length 2 m vibrates in 4 segments. The distance between consecutive nodes is

In stationary wave, the distance between a node and its adjacent antinode is ……….

A string fixed at both ends has consecutive standing wave modes for which the distance between adjacent nodes are 18 cm and 16 cm respectively. The length of the string is -

The string fixed at both ends has standing wave nodes for which distance between adjacent nodes is x_1 . The same string has another standing wave nodes for which distance between adjacent nodes is x_2 . If l is the length of the string then x_2//x_1=l(l+2x_1) . What is the difference in numbers of the loops in the two cases?

A stretched string fixed at both end has n nods, then the lengths of the string is

A string is vibrating in its fifth overtone between two rigid supports 2.4 m apart. The distance between successive node and antinode is

A stretched string is vibrating in the second overtone, then the number of nodes and anti-nodes between the ends of the string are respectivley

When the string of the sonometer of length l between the bridges vibrates in the first overtone, then the antinode formed from one end of the string will be

MOTION-WAVES-EXERCISE -2 (Level -I) (Objective Problems JEE Main)

Two pulses in a stretched string whose centres are initially 8 cm apar...
Text Solution
|
Equations of two progressive waves at a certain point in a medium are ...
Text Solution
|
there are three strings RP, Pqand QS as shown. Their mass and length a...
Text Solution
|
Two pulses in a stretched string whose centres are initially 8 cm apar...
Text Solution
|
Two waves represented by y1 =a sin omega t and y2 =a sin (omega t+phi...
Text Solution
|
A harmonic wave is travelling on string 1. At a junction with string 2...
Text Solution
|
A composite string is made up of two uniform strings having mass per ...
Text Solution
|
In the previous question, the percentage of power transmitted to the h...
Text Solution
|
A wave moving with constant speed on a uniform string passes the point...
Text Solution
|
A metallic wire of length l is held between two rigid supports. If the...
Text Solution
|
In the shown figure answer the following two questions If Pi , Pr...
Text Solution
|
A standing wave y=A sin((20pix)/(3))cos (1000pit) is set up in a taut ...
Text Solution
|
A wave represented by the equation y=acos(kx-omegat) is superposed wit...
Text Solution
|
A taut string at both ends viberates in its n^(th) overtone. The dista...
Text Solution
|
A standing wave pattern of amplitude A in a string of length L shows 2...
Text Solution
|
The equation of a wave distrubance is a given as y= 0.02 sin ((pi)/(...
Text Solution
|
The frequency of a sonometer wire is f . When the weight producting th...
Text Solution
|
A sting of length 1m and linear mass density 0.01 kg//m is stretched t...
Text Solution
|
A uniform string fixed at both ends vibrates in a resonant mode with a...
Text Solution
|
Figure, shows a stationary wave between two fixed points P and Q Which...
Text Solution
|