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Two bodies P and Q have thermal emissivi...

Two bodies P and Q have thermal emissivities of `varepsilon_(P) and varepsilon_Q` respectively. Surface areas of these bodies are same and the total radiant power is also emitted at the same rate. If temperature of P is `theta_P` kelvin then temperature of Q i.e. `theta_Q` is

A

`((varepsilon_Q)/(varepsilon_P))^(1//4) theta_p`

B

`((varepsilon_P)/(varepsilon_Q))^(1//4) theta_p`

C

`((varepsilon_Q)/(varepsilon_P))^(4) theta_p`

D

`((varepsilon_P)/(varepsilon_Q))^(4) theta_p`

Text Solution

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The correct Answer is:
B
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MOTION-HEAT - 1-EXERCISE - 1 Objective Problems | JEE Main
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