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In YDSE, light of wavelength lamda = 500...

In YDSE, light of wavelength `lamda = 5000 Å` is used, which emerges in phase from two slits distance `d = 3 xx 10^(-7) m` apart. A transparent sheet of thickness `t = 1.5 xx 10^(-7) m`, refractive index `n = 1.17`, is placed over one of the slits. Where does the central maxima of the interference now appear from the center of the screen? (Find the value of y?)

Text Solution

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The correct Answer is:
y = 0.085 D ; D = distance between screen & slits
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