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wedge(m)^(@) for NaCl,HCl, and NaAc are1...

`wedge_(m)^(@)` for `NaCl,HCl`, and `NaAc` are`126.4, 425.9,` and `91.0 S cm^(2) mol^(-1)` , respectively . Calculate `wedge ^(@)` for `HAc.`

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`^^_(m("HAc")^(@)=lamda_(H^(+))^(@)+lamda_(AC)^(@)=lamda_(H^(+))^(@)+lamda_(Cl^(-))^(@)+lamda_(Ac^(-))^(@)+lamda_(Na^(+))^(@)-lamda_(Cl^(-))^(@)-lamda_(Na^(+))^(@)`
`=^^_(m(HCl))^(@)+^^_(m(NaAc))^(@)-A_(m(NaCl))^(@)`
`=(425.9+91.0-126.4)S" "cm^(2)mol^(-1)`
`=390.5S" "cm^(2)mol^(-1)`
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