The conductivity of `0.001028 M` acetic acid is `4.95xx10^(-5) S cm^(-1)`. Calculate dissociation constant if `wedge_(m)^(@)` for acetic acid is `390.5 S cm^(2) mol ^(-1)`.

Explanation

`^^_(m)=(k)/(c)=(4.95xx10^(-5)S" "cm^(-1))/(0.001028mol" "L^(-1))xx(1000cm^(3))/(L)=48.15S" "cm^(3)" "mol^(-1)`
`alpha=(^^_(m))/(^^_(m)^(@))=(48.15S" "cm^(3)mol^(-1))/(390.5S" "cm^(2)mol^(-1))=0.1233`
`k=(calpha^(2))/((1-alpha))=(0.00128mol" "L^(-1)xx(0.1233)^(2))/(1-0.1233)=1.78xx10^(-5)mol" "L^(-1)`