Consult the table of standard electrode potential and suggest three substances that can oxidize `Fe^(2+)` ions under suitable conditions.

Explanation

Oxidation of `Fe^(2+)` converts it to `Fe^(3+),` i.e., `Fe^(2+) to Fe^(3+) + e^(-),E_(ox)^(@)=-0.77` only those substances can oxidise `Fe^(2+)` to `Fe^(3+)` which are stronger oxidizing agents and have positive reduction potentials greater than 0.77V, so that EMF of the cell reaction is positive. this is so for elements lying below `Fe^(3+)//Fe^(2+)` in the series ex. `Br_(2),Cl_(2) and F_(2)`.