If a current of `0.5A` flows through a metallic wire for 2 hours, then how many electrons would flow through the wire ?

Explanation

We know
`Q-lt`
`=0.5xx(2xx60xx60)`
`=3600C`
`1Fimplies96500Cimplies1" mole of "e^(-1)`s
`implies6.02xx10^(23)e^(-1)s`
`therefore` 3600 C is equivalent to the flow of `e^(-1)` s
`=(6.02xx10^(23))/(96500)xx3600`
`=2.246xx10^(22)e^(-1)s`