Given standard electrode potentials
`K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`,
`Hg^(2+)|Hg=0.79V`
`Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

Explanation

Higher, the oxidation potential more easily it is oxidized and hence greater is the reducing power. Thus, increasing order of reducing power will be `Ag lt Hg lt Cr lt Mg lt K`.