A solution of `Ni(NO_(3))_(2)` is electrolyzed between platium electrodes using a current of `5A` for `20 mi n`. What mass of `Ni` is deposited at the cathode ?

Explanation

Quantity of electricity passed `=(5A)xx(20xx60sec)=6000C`
`Ni^(2+)to2e^(-)toNi`
thus, 2F, i.e., `2xx96500C` of charge deposite
`=1` mole off Ni=58.7g
`therefore6000C` of charge will deposite
`=(58.7xx6000)/(2xx96500)=1.825g` of Ni.