A hydrocarbon `C_(5)H_(10)` does not react with chlorine in dark but gives a single monochloro compound `C_(5)H_(9)Cl` in bright sunlight. Identify the hydrocarbon.

Explanation

To identify the hydrocarbon \( C_5H_{10} \) that does not react with chlorine in the dark but gives a single monochloro compound \( C_5H_9Cl \) in bright sunlight, we can follow these steps:

### Step 1: Determine the Type of Hydrocarbon
The molecular formula \( C_5H_{10} \) suggests that the hydrocarbon could either be a cycloalkane or an alkene. This is because the formula can be expressed as \( C_nH_{2n} \), which is characteristic of both cycloalkanes and alkenes.

**Hint:** Look at the general formula for alkenes and cycloalkanes to determine their structure.

### Step 2: Analyze the Reactivity with Chlorine
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