A hydraulic automobile lift is designed to lift cars with a maximum mass of 300 kg. the area of cross-section of the piston carrying the load is `425cm^(3)`. What maximum pressure would smaller piston have to bear?

Explanation

Pressure on the piston due to car
`=("Weight of car")/("Area of piston")`
`P=(3000xx9.8)/(425xx10^(-4))Nm^(-2)=6.92xx10^(5)Pa`
This is also the maximum pressure that the smaller piston would have to bear.