The cylinderical tube of a spray pump has a cross-section of `8.0cm^(2)` one end of which has 40 fine holes each of diameter 1.0mm. If the liquid flow inside the tube is 1.5 m per minute, what is the speed of ejection of the liquid through the holes?

Explanation

Total cross-sectional area of 40 hiles, `a_(2)`
`=40xx(22)/(7)xx((1xx10^(-3))^(2))/(4)m^(2)`
`=(22)/(7)xx10^(-5)m^(2)`
cross-sectional are of tube `a_(1)=8xx10^(-4)m^(2)`
speed inside the tube, `v_(1)=1.5m" "mi n^(-1)=(1.5)/(60)ms^(-1)`
speed of ejection `v_(2)=?`
speed of ejection `v_(2)=?`
Using `a_(2)v_(2)=a_(1)v_(1)`
we get
`v_(2)=(a_(1)v_(1))/(a_(2))=(8xx10^(-4)xx(1.5)/(60)xx7)/(22xx10^(-5))ms^(-1)=0.64ms^(-1)`.