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Let veca=hati+2hatj+3hatk, vecb=2hati+3h...

Let `veca=hati+2hatj+3hatk`, `vecb=2hati+3hatj+hatk, vecc=hatk+hati and (vecx xx vecb)=(veca xx vecc)xxvecb`. If `vecx .veca=0` , then `|vecx|` is equal to use `sqrt3=1.73`)``

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