Evaluate the definite integrals`int_0^(pi/2)sin2xtan^(-1)(sinx)dx`

Explanation

let `sinx=t`

thus

`I=int(t.tan^-1tdt)`

thus, on solving we get

`I=t^2tan^-1t-t-+an^-1t`


Now for range 0 and 1

`I=pi/4-1+pi/4-(0-0+0)`

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