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If x=a+a/r+a/(r^2)+oo,y=b-b/r+b/(r^2)+oo...

If `x=a+a/r+a/(r^2)+oo,y=b-b/r+b/(r^2)+oo,a n dz=c+c/(r^2)+c/(r^4)+oo,` prove that `(x y)/z=(a b)/cdot`

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Given,
`x=a+a/r+a/(r^2)+oo,y=b-b/r+b/(r^2)+oo,a n dz=c+c/(r^2)+c/(r^4)+oo,`
the sum of infinite terms is `a/(1-r)`
Given,
`x=a+a/r+a/(r^2)+oo`
here, `a=a` and `r=1/r`
...
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