If `a ,b ,c` are in G.P. and `a^(1//x)=b^(1//y)=c^(1//z),` then `x y z` are in AP (b) GP (c) HP (d) none of these

Explanation

Let `a^(1/x) = b^(1/y) = c^(1/z) = p`

`a = p^x`

`b = p^y`

`c = p^z`

`b^2 = ac` (since a,b,c in GP)

`(p^y)^2 = p^xp^z`

`p^(2y) = p^(x+z)`

Equating powers
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