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prove that a^x - b^y = 0 where x = sqrt...

prove that `a^x - b^y = 0 `where x = `sqrt(log_a b )` and y = `sqrt(log_b a )` , a>0 , b>0 and a , b `!=` 1

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MOTION-BASIC MATHEMATIC & LOGARITHM -Exercise - 3
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  3. 9^(1+log x)- 3^(1+log x) - 210 = 0 , where base of log is 3.

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