Home
Class 12
MATHS
Cartesian equations of a circle whose pa...

Cartesian equations of a circle whose parametric equation are x = – 7 + 4 cos q, y = 3 + 4 sin q is

A

`(x+7)^(2) + (y-3)^(2) = 16`

B

`(x-7)^(2) + (y-3)^(2) = 16`

C

`(x-7)^(2) + (y+3)^(2) = 16`

D

`(x+7)^(2) + (y + 3)^(2) = 16`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    MOTION|Exercise Exercise - 2(Level - I) (Objective Problems | JEE Main)|39 Videos
  • CIRCLE

    MOTION|Exercise Exercise -2 (Level - II) Multiple correct | JEE Advanced|14 Videos
  • CIRCLE

    MOTION|Exercise Exercise - 4 | Level - II (Previous Year | JEE Advanced|22 Videos
  • BINOMIAL THEOREM

    MOTION|Exercise Exercise -4 (Level - II) ( Previous Year )|7 Videos
  • COMPLEX NUMBER

    MOTION|Exercise EXERCISE - 4 (LEVEL -II) PREVIOUS YEAR - JEE ADVANCED|33 Videos

Similar Questions

Explore conceptually related problems

Find the Cartesian euqaiton of that curves whose parametric equation : x= 7 + 4 cos alpha, y = -3 + 4 sin alpha

Find the Cartesian equation of the curves whose parametric equation are : x=3 cos alpha, y = 3 sin alpha

Find the Cartesian equation of the curves whose parametric equation are : x=5 cos theta, y = 5 sin theta

Find the Cartesian equation of the curves whose parametric equation are : x=a+c cos alpha, y = b + c sin alpha

Find the Cartesian equation of the curves whose parametric equation are : x=1 + 3 cos theta, y=2-3 sin theta

Find the Cartesian euqaiton of that curves whose parametric equation : x= 5+3 cos theta, y = 7 + 3 sin theta

Find the Cartesian equation of the curves whose parametric equation are : x=cos theta + sin theta, y = sin theta - cos theta

Find the Cartesian euqaiton of that curves whose parametric equation : x= cos theta + sin theta + 1, y = sin theta - cos theta + 2

Find the equation of curve whose parametric equations are x=2t-3,y=4t^(2)-1 is

MOTION-CIRCLE-Exercise - 1 (Objective Problems | JEE Main)
  1. Find the greatest distance of the point P(10 ,7) from the circle x^2+y...

    Text Solution

    |

  2. The parametric coordinates of any point on the circle x^(2) + y^(2) – ...

    Text Solution

    |

  3. Cartesian equations of a circle whose parametric equation are x = – 7 ...

    Text Solution

    |

  4. Find the equation of the two tangents from the point (0, 1 ) to the ci...

    Text Solution

    |

  5. Find the equation of the normal to the circle x^2+y^2=9 at the point (...

    Text Solution

    |

  6. The length of the tangent drawn from the point (2, 3) to the circles 2...

    Text Solution

    |

  7. Find the angle between the two tangents from the origin to the circle ...

    Text Solution

    |

  8. The point from which the tangents to the circles x^2 +y^2-8x + 40 = 0,...

    Text Solution

    |

  9. The tangent from the point of intersection of the lines 2x – 3y + 1 = ...

    Text Solution

    |

  10. The equation of the circle having the lines y^(2) – 2y + 4x – 2xy = 0 ...

    Text Solution

    |

  11. The equation of director circle to the circle x^(2) + y^(2) = 8 is

    Text Solution

    |

  12. Two perpendicular tangents to the circle x^(2) + y^(2) = a^(2) meet at...

    Text Solution

    |

  13. The locus of the mid-points of the chords of the circles x^2+ y^2-2x-...

    Text Solution

    |

  14. find the locus of mid point of chords of circle x^2 +y^2= 25 which sub...

    Text Solution

    |

  15. The equation to the chord of the circle x^(2) + y^(2) = 16 which is bi...

    Text Solution

    |

  16. The locus of the centers of the circles such that the point (2, 3) is...

    Text Solution

    |

  17. Tangents are drawn from (4, 4) to the circle x^(2) + y^(2) – 2x – 2y –...

    Text Solution

    |

  18. Pair of tangents are drawn from every point on the line 3x + 4y = 12 o...

    Text Solution

    |

  19. The equation of pair of tangents drawn from the point (0,1) to the cir...

    Text Solution

    |

  20. From the point P(16,7), tangents PQ and PR are drawn to the circle x^2...

    Text Solution

    |