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The locus of the mid points of the chord...

The locus of the mid points of the chords of the circle `x^2+y^2-ax-by=0` which subtends a right angle at `(a/2,b/2)` is

A

ax + by = 0

B

`ax + by = a^(2) + b^(2)`

C

`x^(2) + y^(2) - ax - by + (a^(2) + b^(2))/(8) = 0`

D

`x^(2) + y^(2) - ax - by - (a^(2) + b^(2))/(8) = 0`

Text Solution

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The correct Answer is:
C
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