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In a right triangle ABC, right angled at A, on the leg AC as diameter, a semicircle is described. The chord joining A with the point of intersection D of the hypotenuse and the semicircle, then the length AC equals to

A

`(AB.AD)/(sqrt(AB^(2) + AD^(2))`

B

`(AB.AD)/(AB + AD)`

C

`sqrt(AB.AD)`

D

`(AB.AD)/(sqrt(AB^(2).AD^(2))`

Text Solution

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The correct Answer is:
D
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MOTION-CIRCLE-Exercise - 2(Level - I) (Objective Problems | JEE Main)
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