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If P and Q are two points on the circle ...

If `P and Q` are two points on the circle `x^2 + y^2 - 4x + 6y-3=0` which are farthest and nearest respectively from the point `(7, 2)` then. (A) `P-=(2-2sqrt(2), -3-2sqrt(2))` (B) `Q-= (2+2sqrt(2), -3 + 2 sqrt(2))` (C) `P-= (2+2sqrt(2), -3 + 2 sqrt(2))` (D) `Q-= (2-2sqrt(2), -3 + 2 sqrt(2))`

A

`A -= (2-2sqrt(2), -3-2sqrt(2))`

B

`A -= (2 + 2sqrt(2), -3+2sqrt(2))`

C

`B -= (2 + 2sqrt(2), -3 +2 sqrt(2))`

D

`B -= (2-2sqrt(2), -3-2sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
A, C
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