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Consider the circles x^(2) + y^(2) = 1 &...

Consider the circles `x^(2) + y^(2) = 1` & `x^(2) + y^(2) – 2x – 6y + 6 = 0`. Then equation of a common tangent to the two circles is

A

4x – 3y – 5 = 0

B

x + 1 = 0

C

3x + 4y – 5 = 0

D

y – 1 = 0

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The correct Answer is:
A, B, C, D
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