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A tangent PT is drawn to the circle `x^2+y^2=4` at the point `P(sqrt3,1)`. A straight line `L`, perpendicular to `PT` is a tangent to the circle `(x-3)^2+y^2=1` then find a common tangent of the two circles

A

x = 4

B

y = 2

C

`x + sqrt(3)y = 4`

D

`x + 2sqrt(2) y = 6`

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The correct Answer is:
D
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MOTION-CIRCLE-Exercise - 4 | Level - II (Previous Year | JEE Advanced
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  12. A possible equation of L is (A) x 3y 1 (B) x 3y 1 (C) x 3y 1 (D) x...

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  16. Let , RS be the diameter of the circle x^(2) + y^(2) = 1 , where S...

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