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If f(x) = { x, x in Q; -x, x !in Q then ...

If `f(x) = { x, x in Q; -x, x !in Q` then `f` is continuous at

A

only at zero

B

only at 0,1

C

all real numbers

D

all rational numbers

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The correct Answer is:
A
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MOTION-CONTINUITY -EXERCISE -1(SECTION - G SINGLE POINT CONTINUITY)
  1. If f(x) = { x, x in Q; -x, x !in Q then f is continuous at

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