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tan^-1a+tan^-1b, where a > 0, b>0, ab > ...

`tan^-1a+tan^-1b,` where `a > 0, b>0, ab > 1`, is equal to

A

`tan^(-1) ((a+b)/(1-ab))`

B

`tan^(-1) ((a+b)/(1-ab))-pi`

C

`pi+tan^(-1) ((a+b)/(1-ab))`

D

`pi-tan^(-1) ((a+b)/(1.ab))`

Text Solution

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The correct Answer is:
C
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