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In a unique hockey series between India ...

In a unique hockey series between India and Pakistan, they decide to play on till a team wins 5 matches. The number of ways in which the series can be won by India, if no match ends in a draw is

A

126

B

252

C

225

D

none

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the number of ways in which India can win a unique hockey series against Pakistan (where the series continues until one team wins 5 matches), we can break down the solution into clear steps. ### Step-by-Step Solution: 1. **Understanding the Problem**: - India wins the series if they win 5 matches before Pakistan does. - The last match must always be a win for India since they need to reach 5 wins to win the series. 2. **Denoting Wins and Losses**: - Let 'W' represent a win for India and 'L' represent a win for Pakistan. - Since India must win the series, the sequence of matches must end with 'W'. 3. **Counting Matches**: - To find the number of ways India can win the series, we need to consider how many matches can occur before the final match (which is a win for India). - If India wins 5 matches, the maximum number of matches played can be 9 (4 wins for India and 4 wins for Pakistan, followed by the final win for India). 4. **Possible Scenarios**: - India can win the series in the following scenarios: - India wins 5 matches and loses 0 matches (WWWWW). - India wins 5 matches and loses 1 match (e.g., WWWWL). - India wins 5 matches and loses 2 matches (e.g., WWLWW). - India wins 5 matches and loses 3 matches (e.g., WLWLW). - India wins 5 matches and loses 4 matches (e.g., LLLLW). 5. **Calculating Combinations**: - For each scenario, we need to calculate the number of ways to arrange the wins and losses: - For the case where India wins 5 and loses 0: There is only 1 way (WWWWW). - For the case where India wins 5 and loses 1: We need to choose 4 positions for 'W' out of the first 5 matches (the last match is fixed as 'W'). This can be calculated using combinations: \( \binom{5}{4} = 5 \). - For the case where India wins 5 and loses 2: We choose 3 positions for 'W' out of the first 6 matches. This is \( \binom{6}{4} = 15 \). - For the case where India wins 5 and loses 3: We choose 2 positions for 'W' out of the first 7 matches. This is \( \binom{7}{4} = 35 \). - For the case where India wins 5 and loses 4: We choose 1 position for 'W' out of the first 8 matches. This is \( \binom{8}{4} = 70 \). 6. **Summing Up the Combinations**: - Now, we add all the combinations together: - Total ways = \( 1 + 5 + 15 + 35 + 70 = 126 \). ### Final Answer: The total number of ways in which India can win the series is **126**. ---
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In a unique hockey series between India & Pakistan, they decide to play on till a team wins 5 matches The number of ways in which the series can be won by India, if no match ends in a draw is: (A) 126 (B) 252 (C) 225 (D) none

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Knowledge Check

  • In a unique hockey series between India & Pakistan, they decide to play till a team wins 5 matches . The number of ways in which the series can be won by India, if no match ends in a draw is

    A
    126
    B
    252
    C
    225
    D
    none of these
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    A
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    B
    If India will win
    C
    the series
    D
    this match
  • India and Pakistan play a 5 match test series of hockey, the probability that India wins at least three matches is

    A
    `1/2`
    B
    `3/5`
    C
    `4/5`
    D
    None of these
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