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If cotalpha + tanalpha = m and 1/cos a...

If `cotalpha + tanalpha = m` and `1/cos alpha -cos alpha=n`, then

A

`m(mn)^(2)^(1//3)-n(nm^(2))^(1//3)=1`

B

`m(m^(2)n)^(1//3)-n(nm^(2))^(1//3)=1`

C

`n(mn)^(2))^(1//3)-m(nm^(2))^(1//3)=1`

D

`m(m^(2)n)^(1//3)-m(mn^(2))^(1//3)=1`

Text Solution

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The correct Answer is:
A
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MOTION-TRIGNOMETRIC RATIOS & IDENTITIES -Exercise 2(Level -I)
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