The sum of two numbers is `(13)/6dot` An even number of arithmetic means are being inserted between them and sum exceeds their number by `1.` find the number of means inserted.

Explanation

To solve the problem step by step, we will denote the two numbers as \( a \) and \( b \). Given that the sum of these two numbers is \( \frac{13}{6} \), we can express this as:

\[ a + b = \frac{13}{6} \]

Next, we know that an even number of arithmetic means, say \( x \), are inserted between \( a \) and \( b \). The total number of terms in the sequence will then be \( x + 2 \) (including \( a \) and \( b \)).

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