If `(b+c-a)/a ,(b+c-a)/b ,(a+b-c)/c ,` are in A.P., prove that `1/a ,1/b ,1/c` are also in A.P.

Explanation

To prove that if \((b+c-a)/a\), \((b+c-a)/b\), \((a+b-c)/c\) are in Arithmetic Progression (A.P.), then \(1/a\), \(1/b\), \(1/c\) are also in A.P., we can follow these steps:

### Step-by-Step Solution

1. **Understanding A.P. Condition**:
For three numbers \(x\), \(y\), and \(z\) to be in A.P., the condition is:
\[
2y = x + z
...