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Integrate the functions1/(x(logx)^m), x ...

Integrate the functions`1/(x(logx)^m), x >0`

Text Solution

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Given,`1/(x(logx)^m), x >0`
Putting `logx=t`
=`1/x​dx=dt`
⇒`∫1/[x(logx)^m]​dx=∫dt/(t)^m​`
=`[t^((−m+1)​)]/(1−m)+C`
=`[logx^((−m+1)​)+]/(1−m)+C`
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