A particle having mass m is projected with a velocity `v_(0)` from a point P on a horizontal ground making an angle `theta` with horizontal. Find out the torque about the point of projection acting on the particle when
it is at its maximum height ?

Explanation

Particle is at maximum height then `tau` about point P
is ` tau_(P) = r_(bot) = (R)/(2)`
`rArr tau_(p) = (R)/(2) mg = mg xx (V_(0)^(2) sin 2 theta)/(2g)`
` tau_(p)= (mv_(0)^(2)sin 2 theta)/(2)`