A child with mass `m` is standing at the edge of a disc with moment of inertia `I`, radius `R`m and initial angular velocity `omega`. See figure given below. The chlid jumps off the edge of the disc with tangential velocity `v` with respect to the ground. The new angular velocity of the disc is.
.

Options

A. `sqrt((I omega^(2) - mv^(2))/(I))`
B. `sqrt(((I+mR^(2))omega^(2)-mv^(2))/(I))`
C. `(Iomega - mv R)/(I)`
D. `((I + mR^(2))omega - mv R)/(I)`

Answer

D