One ice sketer of mass m moves with speed 2v to the right, while another of the same mass m moves with speed v toward the left, as shown in figure I . Their paths are separated by a distance b. At t = 0 when they are both at x = 0, they grasp a poleof length b and negligible mass . For `t gt 0, ` consider the system as a rigid body of two masses m separated by distance b, as shown in figure II . Which of the following is the correct formula for the motion after t = 0 of the skater initially at y = b/2 ?

Options

A. x = 2 vt , y = b/2
B. `x = vt + 0.5b sin (3 vt //b) , y = 0 . 5 b cos (3 vt //b)`
C. `x = 0 . 5 vt + 0 . 5 b sin (3 vt//b) , y = 0 . 5 b cos (3 vt //b)`
D. `x = 0 . 5 vt + 0 . 5b sin (6 vt //b) , y = 0 .5 b cos (6 vt //b)`

Answer

C