A ring and a disc are initially at rest, side by side, at the top of an inclined plane which makes an angle `60^(@)` with the horizontal. They start to roll without slipping at the same instant of time along the shortest path. If the time difference between their reaching the ground is `(2 - sqrt(3)) //sqrt(10s)` 2– 3 / 10s, then the height of the top of the inclined plane, in metres, is _____________ . Take `g = 10ms^(-2)`

Answer

`0.86` M