Home
Class 12
PHYSICS
A point charge q is placed at a distance...

A point charge q is placed at a distance `(a)/(2)` directly above the centre of a horizontal square of side 'a' and another point charge -q is placed at a distance 'a' directly below one of its (the square's) corners. The electric flux through the square is :

A

`(q)/(6 in_(0))`

B

`(q)/(8in_(0))`

C

`(q)/(24in_(0))`

D

`(5q)/(24in_(0))`

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROSTATICS-II

    MOTION|Exercise Exercise 1 (Section B - Properties of conductors)|15 Videos

  • ELECTROSTATICS-II

    MOTION|Exercise Exercise 1 (Section C - Spheres Problem, Electrostatics pressure)|16 Videos

  • ELECTROSTATICS-II

    MOTION|Exercise Exercise - 4 (Level - II)|30 Videos

  • ELECTROSTATICS - I

    MOTION|Exercise EXERCISE - 4 (Level -II) PREVIOUS YEAR - JEE ADVANCED|13 Videos

  • ERRORS , THEORY

    MOTION|Exercise EXERCISE 4 (LEVEL -II)|10 Videos

Similar Questions

Explore conceptually related problems

A point charge of +6mu C is placed at a distance 20 cm directly above the centre of a square of side 40 cm. The magnitude of the flux through the square is

A point charge q is placed at a distnace a/2 directly above the centre of a square of side a, as shown figure. Find the magnitude of the electric flux through the square.

Knowledge Check

  • A point charge q is placed at a distance a//2 directly above the centre of a square of side a . The electric flux through the square is

    A
    `(q)/(epsilon_(0))`
    B
    `(q)/(piepsilon_(0))`
    C
    `(q)/(4epsilon_(0))`
    D
    `(q)/(6epsilon_(0))`

  • A point charge of +6 muC is placed at a distance 20 cm directly above the centre of a square of side 40 cm . The magnitude of the flux through the square is

    A
    `epsilon_(0)`
    B
    `(1)/(epsilon_(0))`
    C
    `epsilon_(0) xx 10^(-6)`
    D
    `(1)/(epsilon_(0))xx 10^(-6)`

  • a point charge q is placed at the centre of a cylinder of length L and radius R the electric flux through the curved surface of the cylinder is

    A
    `(q)/(epsilon_(0))(L)/(sqrt(L^(2)+R^(2)))`
    B
    `(q)/(epsilon_(0))(L)/(sqrt(L^(2)+2R^(2)))`
    C
    `(q)/(epsilon_(0))(L)/(sqrt(L^(2)+4R^(2)))`
    D
    `(q)/(2epsilon_(0))`

    • Similar Questions

    Explore conceptually related problems

    A point charge q is placed at a distance d form the center of circular disc of radius R . Find electric flux through the disc due to that charge

    A point charge +20muC is at a distance 6 cm directly above the centre of a square of side 12 cm as shown is figure. The magnitude of electric flux through the square is

    (a) Define electric flux. Is is the scalar or a vector quantity? A point charge q is at a distance of d//2 directly above the centre of a square of side d, as shown in the figure. Use Gauss's law to obtain the expression for the electric flux through the square. (b) If the point charges is now moved to a distance 'd' from the centre of the square and the side of the square is doubled, explain how the electric flux will be affected.

    A point charge Q is placed at the corner of a square of side a, then find the flux through the square.

    A charge Q is placed at a distance alpha/2 above the centre of a horizontal, spuare surface of edge a as shown in figure (30-E1). Find the flux of the electric field through the square surface.

    Home
    Profile