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The electric field intensity at the cent...

The electric field intensity at the center of a uniformly charged hemispherical shell is `E_(0)`. Now two portions of the hemisphere are cut from either side, and the remaining portion is shown in fig. If `alpha=beta=pi//3`, then the electric field intensity at the center due to the remaining portion is

A

`(E_(0))/(3)`

B

`(E_(0))/(6)`

C

`(E_(0))/(2)`

D

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The correct Answer is:
C
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MOTION-ELECTROSTATICS-II-Exercise 1 (Section A-Questions Based on electric flux for various configuration, Question on solid angle concept, Gauss law Based Questions)
  1. Statement - 1 : The flux crossing through a closed surface is independ...

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  2. Statement -1 : Electric field of a dipole can't be found using only Ga...

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  3. In a region of space the electric field in the x-direction and proport...

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  4. Electric flux through a surface of area 100m^2 lying in the xy plane ...

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  5. A cylinder of radius R and length l is placed in a uniform electric fi...

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  6. The volume charge density as a function of distance X from one face in...

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  7. A hemisphere (radius R) is placed in electric field as shown in fig. T...

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  8. An arbitrary surface encloses a dipole. What is the electric flux thro...

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  9. Electric charges are distributed in a small volume. The flux of the el...

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  10. A uniform electric field ahati +bhatj intersects a surface of area A. ...

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  11. A uniformly charged and infinitely long line having a linear charge de...

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  12. Two spherical conductors A and B of radii 1mm and 2mm are separated by...

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  13. A point charge q is placed at the centre of a spherical shell of radiu...

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  14. A wire of linear charge density lambda passes through a cuboid of leng...

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  15. A point charge q is placed at a distance (a)/(2) directly above the ce...

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  16. The electric field intensity at the center of a uniformly charged hemi...

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