The photoelectric threshold of the photo electric effect of a certain metal is `2750 A^(@)`. Find
(i) The work function of emission of an electron from this metal,
(ii) Maximum kinetic energy of these electrons.
(iii) The maximum velocity of the electrons ejected from the metal by light with a wavelength `1800 A^(@)`.

Explanation

If the maximum speed of ejected electrons is `v_max` then we have
`(1)/(2)mv²_max` = 2.38eV
or
`v_max` = `sqrt{(2xx2.38xx1.6xx10^(-19))/(9.1xx10^(-11))} = 9.15 xx10^(5) m//s`