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The dimensions of a mangnin block are 1 ...

The dimensions of a mangnin block are `1 cm xx 1 cm xx100 cm` The electrical resistivity of mangnin is `4.4 xx10^(-7)` ohm–meter. The resistance between the opposite rectangular faces is –

A

`4.4 xx10^(-7)` ohm

B

`4.4 xx10^(-3)` ohm

C

`4.4 xx10^(-5)` ohm

D

`4.4 xx10^(-1)` ohm

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To find the resistance between the opposite rectangular faces of a manganin block with dimensions \(1 \, \text{cm} \times 1 \, \text{cm} \times 100 \, \text{cm}\) and an electrical resistivity of \(4.4 \times 10^{-7} \, \Omega \cdot \text{m}\), we will use the formula for resistance: \[ R = \frac{\rho L}{A} \] where: - \(R\) is the resistance, - \(\rho\) is the resistivity, - \(L\) is the length of the conductor, - \(A\) is the cross-sectional area. ### Step 1: Identify the dimensions The dimensions of the manganin block are: - Length (\(L\)) = \(100 \, \text{cm}\) - Cross-sectional area (\(A\)) = \(1 \, \text{cm} \times 1 \, \text{cm}\) ### Step 2: Convert dimensions to meters To use the resistivity in ohm-meters, we need to convert the dimensions from centimeters to meters: - Length (\(L\)) = \(100 \, \text{cm} = 1 \, \text{m}\) - Cross-sectional area (\(A\)) = \(1 \, \text{cm} \times 1 \, \text{cm} = (0.01 \, \text{m}) \times (0.01 \, \text{m}) = 0.0001 \, \text{m}^2 = 10^{-4} \, \text{m}^2\) ### Step 3: Substitute values into the resistance formula Now we can substitute the values into the resistance formula: \[ R = \frac{4.4 \times 10^{-7} \, \Omega \cdot \text{m} \times 1 \, \text{m}}{10^{-4} \, \text{m}^2} \] ### Step 4: Calculate the resistance Calculating the resistance: \[ R = \frac{4.4 \times 10^{-7}}{10^{-4}} = 4.4 \times 10^{-3} \, \Omega \] ### Final Answer The resistance between the opposite rectangular faces of the manganin block is: \[ R = 4.4 \times 10^{-3} \, \Omega \] ---
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Knowledge Check

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