Find out the angle made by `(hati+hatj)` vector from X and Y axes respectively.

Explanation

`cos alpha =(a_(x))/(a) and cos beta=(a_(y))/(a)`
here `a=sqrt(a_(x)^(2)+a_(y)^(2))=sqrt(1^(2)+1^(2))=sqrt(2)`


`cos alpha=(1)/(sqrt(2))`
or `alpha=45^(@)`
`cos beta= (1)/(sqrt(2))`
or `beta=45^(@)` i.e. `hati+hatj` is at bisector of X and Y axes.