Find out the angle made by `vecA= hati+hatj+hatk` vector from X, Y and Z axes respectively.

Explanation

`cos alpha=(A_(x))/(A), " " cos beta=(A_(y))/(A), " " cos gamma= (A_(z))/(A)`
here `A_(x)=A_(y)=A_(z)=1`
and `A=sqrt(A_(x)^(2)+A_(y)^(2)+A_(z)^(2))=sqrt(1+1+1)=sqrt(3)`
`therefore cos alpha=(1)/(sqrt(3)) or alpha = cos^(-1) ((1)/(sqrt(3)))`
`cos beta=(1)/(sqrt(3)) or beta =cos^(-1) ((1)/(sqrt(3)))`
`cos gamma = (1)/(sqrt(3)) or gamma = cos^(-1) ((1)/(sqrt(3)))`