The diagonals of a parallelogram are vectors `vecA and vecB`. If `vecA=5hati-4hatj+3hatk and vecB=3hati-2hatj-hatk`. Calculate the magnitude of area of this parallelogram.

Explanation

When `vecA and vecB` are the diagonals of a parallelegram, then its
Area `=(1)/(2)|vecA xx vecB|=(1)/(2)|(hati, hatj, hatk),(5,-4,3),(3,-2,1)|`
`=(1)/(2) |hati(4+6)-hatj(-5-9)+hatk(-10+12)|`
`=(1)/(2) |10hati +14hatj+2hatk|=(1)/(2) sqrt(10^(2)+14^(2)+2^(2))`
`=(1)/(2) sqrt(300)=(10)/(2) sqrt(3)=5sqrt(3)` unit