A road makes a `90^(@)` bend with a radius of 190 m. A car enters the bend moving at 20 m/s. Finding this too fast, the driver decelerates at 0.92 m/`s^(2)`. Determine the acceleration of the car when its speed rounding the bend has dropped to 15 m/s.

Explanation

Since it is rounding a curve, the car has a radial acceleration associated with its changing direction, in addition to the tangential deceleration that changes its speed. We are given that `a_(t)` = 0.92 m/`s^(2)`, since the car is slowing down, the tangential acceleration is directed opposite the velocity.
The radial acceleration is `a_(r)`
`= (v^(2))/(r ) = ((15m//s)^(2))/(190 m) = 1.2 " " m//s^(2)`