A satellite of mass `10^(7)` kg is revolving around the earth with a time period of 30 days at a height of 1600 km. Find out the force of attraction on satellite by earth?

Explanation

Force = m `omega^(2)R and (2pi)/(T) = (2xx 3.4)/(30xx86400) = (6.26)/(2.59xx 10^(6))`
Force = m`omega^(2)r = ((6.28)/(2.59xx10^(6)))^(2) xx 10^(7) xx(6400 + 1600) xx 10^(3)`
= 2.34 `xx 10^(6)` N