A 62 kg woman is a passenger in a “rotor ride” at an amuse ment park. A drum of radius 5.0 m is spun with an angular velocity of 25 rpm. The woman is pressed against the wall of the rotatingdrum as shown in figure (a) Calculate the normal force of the drum of the woman (the centripetal force that prevents her from leaving her circular path). (b) While the drum rotates, the floor is lowered. A vertical static friction force supports the woman’s weight. What must the coefficient of friction be to support her weight

Explanation

Normal force exerted by the drum on woman towards the centre
`F_(N) = ma_(c) = m omega^(2) r `
= 62 kg `xx (25 ("rev")/("min") xx (2pi rad)/(1 rev) xx (1min )/(60s))^(2) xx 5m = 2100` N
(b) `mu F_(N) = F = mg " "`……(2)
dividing eqn. (2) be eq. (1)
`mu = (g)/(omega^(2)r) = ((60)/(2pi xx 25))^(2) xx (10)/(5) = 0.292`