A small body of mass m = 0.1 kg swings in a vertical circle at the end of a chord of length 1 m. Its speed is 2 m/s when the chord makes an angle `theta = 30^(@)` with the vertical. Find the tension in the chord.

Explanation

The equation of motion is
T - mg cos `theta = (mv^(2))/(r ) `
or T = mg cos `theta + (mv^(2))/(r )`
Substuting the given values, we get
T = 0.1 `xx 9.8 xx `cos 30 + `(0.1 xx (2)^(2))/(1)`
= 0.98 ` xx ((sqrt(3))/(2))` + 0.4
= 0.85 + 0.4 = 1.25 N