How much energy is released when `2 ` mole of `U^(235)` is fission :

Options

A. ` 10^(24) Me V`
B. ` 24 xx 10^(25) Me V`
C. ` 10 ^(24) J`
D. ` 10^(24) kWh`

Answer

To find the energy released when 2 moles of uranium-235 undergo fission, we can follow these steps:

### Step 1: Determine the energy released by one atom of uranium-235 during fission.
- It is given that the energy released from the fission of one atom of uranium-235 is 200 mega electron volts (MeV).

### Step 2: Calculate the number of atoms in 1 mole of uranium-235.
- Using Avogadro's number, which is approximately \(6.022 \times 10^{23}\) atoms/mole, we can find the number of atoms in 1 mole.

### Step 3: Calculate the energy released by 1 mole of uranium-235.
- The energy released by 1 mole of uranium-235 can be calculated as:
\[ \text{Energy from 1 mole} = \text{Energy per atom} \times \text{Number of atoms in 1 mole} \]
\[ = 200 \, \text{MeV} \times 6.022 \times 10^{23} \, \text{atoms} \]

### Step 4: Calculate the energy released by 2 moles of uranium-235.
- Since we need the energy for 2 moles, we multiply the energy released by 1 mole by 2:
\[ \text{Energy from 2 moles} = 2 \times (200 \, \text{MeV} \times 6.022 \times 10^{23}) \]

### Step 5: Perform the calculation.
- First, calculate the energy for 1 mole:
\[ \text{Energy from 1 mole} = 200 \times 6.022 \times 10^{23} = 1.2044 \times 10^{26} \, \text{MeV} \]
- Now for 2 moles:
\[ \text{Energy from 2 moles} = 2 \times 1.2044 \times 10^{26} = 2.4088 \times 10^{26} \, \text{MeV} \]

### Step 6: Convert the energy into a more manageable form.
- Since the answer is typically expressed in mega electron volts (MeV), we convert:
\[ 2.4088 \times 10^{26} \, \text{MeV} = 2.4088 \times 10^{20} \, \text{MeV} \]

### Final Answer:
- The energy released when 2 moles of uranium-235 undergo fission is approximately \(2.4088 \times 10^{20} \, \text{MeV}\).

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