Home
Class 12
PHYSICS
The length of a simple pendulum is 39.2/...

The length of a simple pendulum is `39.2//pi^(2)` m. If `g=9.8 m//s^(2)` , the value of time period is

A

4 sec.

B

8 sec.

C

2 sec.

D

3 sec.

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    MOTION|Exercise EXERCISE -3 Section - A Previous Year Problems | NEET|24 Videos
  • SIMPLE HARMONIC MOTION

    MOTION|Exercise EXERCISE -3 Section - B Previous Year Problems | JEE MAIN|23 Videos
  • SIMPLE HARMONIC MOTION

    MOTION|Exercise EXERCISE -1 (Objective Problems | NEET) SECTION-E Simple Pendulum|6 Videos
  • SEMI CONDUCTOR AND LOGIC GATES

    MOTION|Exercise EXERCISE 3|34 Videos
  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -4 (Leve-II) [ JEE 2011]|11 Videos

Similar Questions

Explore conceptually related problems

What is second's pendulum ? Find the length of second's pendulum for g = 9.8 m//s^(2) ? Also write expressions for the time period if the second's pendulum is an a carriage which is accelerating (a) upwards (b) downwards (c ) horizontally. Also, fin the value of time period of it if is made to oscillate a freely falling lift.

The time period of a simple pendulum of length 9.8 m is

The time period of a simple pendulum is given by the formula, T = 2pi sqrt(l//g) , where T = time period, l = length of pendulum and g = acceleration due to gravity. If the length of the pendulum is decreased to 1/4 of its initial value, then what happens to its frequency of oscillations ?

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

The time period of simple pendulum is T. If its length is increased by 2%, the new time period becomes

A second's pendulum is oscillating at a place where g = 9.8 m//s^(2) . If the pendulum is shifted to a place where g = 9.6 m//s^(2) , then to keep this time period unchanged, how much change of length should be introduced ?

The length of a second's pendulum on the surface of the earth, where g=9.8 m//s^(2) , is approximately equal to

MOTION-SIMPLE HARMONIC MOTION-EXERCISE -2 (Objective Problems | NEET)
  1. The time period of an oscillating body executing SHM is 0.05 sec and i...

    Text Solution

    |

  2. The mass of a bob, suspended in a simple pendulum, is halved from the ...

    Text Solution

    |

  3. The length of a simple pendulum is 39.2//pi^(2) m. If g=9.8 m//s^(2) ...

    Text Solution

    |

  4. A hollow sphere is taken as bob of a simple pendulum. This hollow sphe...

    Text Solution

    |

  5. The length of a second pendulum is

    Text Solution

    |

  6. The acceleration due to gravity at height R above the surface of the e...

    Text Solution

    |

  7. An oscillating pendulum stops, because its energy

    Text Solution

    |

  8. If the length of a simple pendulum is equal to the radius of the earth...

    Text Solution

    |

  9. when the bob of a simple pendulum swings, the work done by tension in ...

    Text Solution

    |

  10. A body of mass 5 gm is executing S.H.M. about a point with amplitude 1...

    Text Solution

    |

  11. The velocity-time diagram of a harmonic oscillator is shown in the adj...

    Text Solution

    |

  12. The distance between the points of suspension and centre of oscillatio...

    Text Solution

    |

  13. For a compound pendulum, the maximum time period is :

    Text Solution

    |

  14. If the distance between the cnetre of gravity and point of suspension ...

    Text Solution

    |

  15. A ring of radius R is suspended from its circumference and is made to ...

    Text Solution

    |

  16. A disc of radius R is suspended from its circumference and made to osc...

    Text Solution

    |

  17. In the above question, its length equivalent to a simple pendulum will...

    Text Solution

    |

  18. Holes are drilled along the diameter of a disc. For a minimum time per...

    Text Solution

    |

  19. The formula for time period of a compound pendulum is :

    Text Solution

    |

  20. The mass of a solid body is 200 gm and oscillates about a horizontal a...

    Text Solution

    |