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A particle executes linear simple harmon...

A particle executes linear simple harmonic motion with an amplitude of `3 cm`. When the particle is at `2 cm` from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is

A

`(sqrt5)/(2 pi)`

B

`(4 pi)/(sqrt5)`

C

`(2 pi)/(sqrt3)`

D

`( sqrt5)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
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MOTION-SIMPLE HARMONIC MOTION-EXERCISE -3 Section - A Previous Year Problems | NEET
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